The given reaction involves a nucleophilic substitution (SN2) where sodium cyanide (NaCN) is used as the nucleophile and DMF is the solvent. In this reaction, the cyanide ion (CN−) will attack the electrophilic carbon attached to the halide group (Cl or I) and replace it.
The structure of the reactant is:
C6H4ClI
When NaCN is added, the cyanide ion (CN−) will substitute for the halide group, leading to the formation of a nitrile group (CN).
The major product of this reaction will be:
C6H4CN
Thus, the major product is the compound (C) Iodobenzene with one CN group attached to the benzene ring.
(i) What is a rate determining step?
A beam of light of wavelength \(\lambda\) falls on a metal having work function \(\phi\) placed in a magnetic field \(B\). The most energetic electrons, perpendicular to the field, are bent in circular arcs of radius \(R\). If the experiment is performed for different values of \(\lambda\), then the \(B^2 \, \text{vs} \, \frac{1}{\lambda}\) graph will look like (keeping all other quantities constant).