Question:

The magnetic flux density created by an infinitely long conductor carrying a current \(I\) at a radial distance \(R\) is:

Show Hint

Ampere’s Law states that the line integral of the magnetic field around a closed path is proportional to the enclosed current.
Updated On: Mar 26, 2025
  • \( \frac{\mu_0 I}{2\pi R} \)
  • \( \frac{1}{2\pi R} \)
  • \( \frac{\mu_0 I}{2\pi R^3} \)
  • \( \frac{4\pi R^2 I}{3} \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

According to Ampere’s Circuital Law, the magnetic field \(B\) around a long straight conductor carrying current \(I\) at a distance \(R\) is given by:
\[ B = \frac{\mu_0 I}{2\pi R} \] Since the magnetic flux density \(B\) represents the same quantity.
Was this answer helpful?
0
0

Top Questions on Electromagnetism

View More Questions