The general equation for a line in parametric form is given by:
\[
\frac{x - 2}{3} = \frac{y - 3}{4} = \frac{z - 4}{5}
\]
Let \( t \) be the parameter, so the parametric equations of the line become:
\[
x = 3t + 2, \quad y = 4t + 3, \quad z = 5t + 4
\]
We are given that the line is parallel to a plane. The direction ratios of the line are \( \langle 3, 4, 5 \rangle \), and the normal to the plane will have the same direction ratios. Therefore, the equation of the plane can be written as:
\[
2x + y - 2z = 0
\]
Thus, the correct answer is \( 2x + y - 2z = 0 \).