Step 1: Using the formula for the length of a seconds pendulum.
The period \( T \) of a seconds pendulum is given by:
\[
T = 2\pi \sqrt{\frac{L}{g}}
\]
Where \( L \) is the length of the pendulum and \( g \) is the acceleration due to gravity. For a planet with double the mass and diameter of the earth, the gravity will be different.
Step 2: Finding the new length.
Since \( g \) is proportional to the mass of the planet and inversely proportional to the square of the radius, we calculate the new gravity on the planet. For double the mass and diameter, gravity becomes half of the earth's gravity.
\[
L_{\text{new}} = \frac{L_{\text{earth}}}{\sqrt{2}} = \frac{1}{\sqrt{2}} \approx 0.3 \, \text{m}
\]
Thus, the correct answer is (C) 0.3 m.