To find the least number which is a perfect square and divisible by 14, 16, and 18, we need to follow these steps:
1. Find the LCM:
Prime factorize each number:
The LCM is found by taking the highest power of all prime factors appearing in the factorizations.
2. Make the LCM a perfect square:
The number 1008 needs to be 'completed' to be a perfect square. The prime factorization of 1008 is:
To make it a perfect square, each prime's exponent must be even. Exponents of 2 and 3 are already even, but 7's exponent (1) is odd, so we multiply by 7.
\(1008 \times 7 = 7056\)
Prime factorization of 7056: \(2^4 \times 3^2 \times 7^2\). All exponents are now even, making 7056 a perfect square.
Therefore, the smallest perfect square divisible by 14, 16, and 18 is 7056.
Option | Value |
A | 6048 |
B | 7056 |
C | 1008 |
D | 2046 |
Correct Answer: 7056
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: