Step 1: Prime factorization
- $12 = 2^2 \times 3$
- $15 = 3 \times 5$
- $21 = 3 \times 7$
Step 2: Take highest powers of all primes
\[
LCM = 2^2 \times 3 \times 5 \times 7
\]
\[
LCM = 4 \times 3 \times 5 \times 7 = 420
\]
Step 3: Re-check options
The $LCM(12, 15, 21) = 420$.
So, the correct answer is option (D).
Find the unknown frequency if 24 is the median of the following frequency distribution:
\[\begin{array}{|c|c|c|c|c|c|} \hline \text{Class-interval} & 0-10 & 10-20 & 20-30 & 30-40 & 40-50 \\ \hline \text{Frequency} & 5 & 25 & 25 & \text{$p$} & 7 \\ \hline \end{array}\]
Two concentric circles are of radii $8\ \text{cm}$ and $5\ \text{cm}$. Find the length of the chord of the larger circle which touches (is tangent to) the smaller circle.