Step 1: Prime factorization
- $12 = 2^2 \times 3$
- $15 = 3 \times 5$
- $21 = 3 \times 7$
Step 2: Take highest powers of all primes
\[
LCM = 2^2 \times 3 \times 5 \times 7
\]
\[
LCM = 4 \times 3 \times 5 \times 7 = 420
\]
Step 3: Re-check options
The $LCM(12, 15, 21) = 420$.
So, the correct answer is option (D).