Step 1: Relation between LCM and HCF
For two numbers $a$ and $b$:
\[
LCM(a, b) \times HCF(a, b) = a \times b
\]
Step 2: Apply the formula
Here $a = 35$, $b = 63$, and $LCM(35, 63) = 315$.
\[
HCF(35, 63) = \dfrac{a \times b}{LCM(a, b)}
\]
\[
HCF = \dfrac{35 \times 63}{315}
\]
\[
HCF = \dfrac{2205}{315} = 7
\]
Step 3: Conclusion
Thus, the $HCF(35, 63) = 7$.
The correct answer is option (B).
Find the unknown frequency if 24 is the median of the following frequency distribution:
\[\begin{array}{|c|c|c|c|c|c|} \hline \text{Class-interval} & 0-10 & 10-20 & 20-30 & 30-40 & 40-50 \\ \hline \text{Frequency} & 5 & 25 & 25 & \text{$p$} & 7 \\ \hline \end{array}\]
Two concentric circles are of radii $8\ \text{cm}$ and $5\ \text{cm}$. Find the length of the chord of the larger circle which touches (is tangent to) the smaller circle.