HCF of X and Y =\(\frac{product}{LCM}=\frac{2700}{180}=15\)
Let Y = 15a and given X is completely divisible by Y, then
X = 15ab
For HCF of X and Y to be 15, a must be 1.
So, X = 15b and Y = 15
Now, product of two numbers = 2700
15b × 15 = 2700
⇒ b = 12
So, (X – Y) = 15(12 – 1) = 15 × 11 = 165.
So, The correct option is (D) : 165.