Kinetic energy is:
\[
K = \frac{1}{2} m v^2
\]
A 21% increase in kinetic energy means:
\[
K_{\text{new}} = 1.21 K
\]
Since \( v_{\text{new}}^2 = 1.21 v^2 \), taking the square root:
\[
v_{\text{new}} = \sqrt{1.21} v \approx 1.1 v
\]
Momentum is \( p = mv \), so an increase in velocity by 10% means momentum also increases by 10%.