Question:

The IUPAC name of the following compound is: 

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Always number from the end nearest to the highest-priority group (here, the –OH). - Ensure correct locants for substituents and the double bond.
Updated On: Mar 11, 2025
  • 6-ethyl-2-methyldec-4-en-7-ol
  • 2-methyl-6-ethyldec-4-en-7-ol
  • 5-ethyl-9-methyldec-6-en-4-ol
  • 9-methyl-5-ethyldec-6-en-4-ol
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The Correct Option is C

Solution and Explanation

Step 1: Longest Chain and Main Functional Group

  • The parent chain has 10 carbons (dec).
  • There is an alcohol (–OH) group, which gets priority in numbering.

Step 2: Numbering and Locating the Double Bond

  • The OH ends up at C-4.
  • The double bond is at C-6 (hence “dec-6-en-4-ol”).

Step 3: Substituents

  • There is an ethyl group at C-5 and a methyl group at C-9.

Putting it all together, the correct IUPAC name is 5-ethyl-9-methyldec-6-en-4-ol.

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