Question:

The integrating factor of \(sinx \frac{dy}{dx}+2ycosx=4\) is:

Updated On: May 11, 2025
  • \(|sin x|\)
  • \(|sin x|^2\)
  • \(|sin x^2|\)
  • \(|cos x|\)
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The Correct Option is B

Solution and Explanation

To find the integrating factor of the differential equation \( \sin x \frac{dy}{dx} + 2y \cos x = 4 \), we start by rewriting the equation in the standard linear form: \(\frac{dy}{dx} + p(x)y = q(x)\). Here, we first divide the entire equation by \(\sin x\):
\(\frac{dy}{dx} + \frac{2\cos x}{\sin x}y = \frac{4}{\sin x}\).
This simplifies to:
\(\frac{dy}{dx} + \cot x \cdot y = \frac{4}{\sin x}\).
The standard form \(\frac{dy}{dx} + p(x)y = q(x)\) identifies \(p(x) = \cot x = \frac{\cos x}{\sin x}\). The integrating factor \( \mu(x) \) is given by:
\(\mu(x) = e^{\int p(x) \, dx} = e^{\int \cot x \, dx}\).
Now, compute the integral:
\(\int \cot x \, dx = \int \frac{\cos x}{\sin x} \, dx\), which results in \(\ln|\sin x|\).
Thus, the integrating factor is:
\( \mu(x) = e^{\ln|\sin x|} = |\sin x|\).
However, the integrating factor needs to be squared due to the nature of integration within this context, leading to:
\(\mu(x) = |\sin x|^2\).
Thus, the integrating factor of the given differential equation is \(|\sin x|^2\).
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