Question:
The instantaneous voltage of a $50\,Hz$ generator giving peak voltage as $300\,V$. The generator equation for this voltage is
The instantaneous voltage of a $50\,Hz$ generator giving peak voltage as $300\,V$. The generator equation for this voltage is
Updated On: May 12, 2024
- $V = 50 \, \sin \, 300\pi t$
- $V = 300 \, \sin \, 100\pi t$
- $V = 6 \, \sin \, 100\pi t$
- $V = 50 \, \sin \, 100\pi t$
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The Correct Option is B
Solution and Explanation
Here, frequency of generator, $v = 50\, {Hz}$
peak voltage, $V_0 = 300\, V$
Instantaneous voltage of the generator,
$V = V_0 \sin\, \omega t = V_0 \sin\, 2\pi vt = 300 \, \sin \, 100 \pi t$
peak voltage, $V_0 = 300\, V$
Instantaneous voltage of the generator,
$V = V_0 \sin\, \omega t = V_0 \sin\, 2\pi vt = 300 \, \sin \, 100 \pi t$
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Concepts Used:
AC Voltage
When voltage changes its direction after every half cycle is known as alternating voltage. The current flows in the circuit at that time are known as alternating current. The alternating current(AC) follows the sine function which changes its polarity concerning time. Most of the electrical devices are operating on the ac voltage.
