Question:

The incorrect statement is :

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General reactivity order for halogens and interhalogens: \(F_2 >\) Interhalogens \(> Cl_2>Br_2>I_2\). The polar nature of the interhalogen bond makes it easier to break during reactions.
Updated On: Dec 31, 2025
  • \(Cl_2\) is more reactive than \(ClF\)
  • \(F_2\) is more reactive than \(ClF\)
  • On hydrolysis \(ClF\) forms \(HOCl\) and \(HF\)
  • \(F_2\) is a stronger oxidizing agent than \(Cl_2\) in aqueous solution
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
Interhalogen compounds (\(X-X'\)) are generally more reactive than the corresponding halogens (except \(F_2\)) because the \(X-X'\) bond is weaker than the \(X-X\) bond due to difference in electronegativity and size.
Step 2: Detailed Explanation:
1. Statement (A): \(ClF\) is an interhalogen compound. Because the \(Cl-F\) bond is weaker than the \(Cl-Cl\) bond, \(ClF\) is more reactive than \(Cl_2\). Thus, Statement (A) is incorrect.
2. Statement (B): \(F_2\) is the most reactive of all halogens due to its low bond dissociation enthalpy and small size. It is more reactive than \(ClF\). Statement (B) is correct.
3. Statement (C): During hydrolysis of interhalogens, the more electronegative halogen forms a hydrohalic acid (\(HX\)) and the less electronegative one forms a hypohalous acid (\(HOX'\)).
\[ ClF + H_2O \to HOCl + HF \]
Statement (C) is correct.
4. Statement (D): Fluorine has the highest reduction potential (\(+2.87 \text{ V}\)) compared to Chlorine (\(+1.36 \text{ V}\)), making it a much stronger oxidizing agent. Statement (D) is correct.
Step 3: Final Answer:
The incorrect statement is "\(Cl_2\) is more reactive than \(ClF\)".
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