The I-V characteristics of an electronic device shown in the figure. The device is
- a solar cell
- a transistor which can be used as an amplifier
- a zener diode which can be used as voltage regulator
- a diode which can be used as a rectifier
The Correct Option is C
Approach Solution - 1
The given question involves analyzing the I-V characteristics of an electronic device to determine its type. The options provided are:
- A solar cell
- A transistor which can be used as an amplifier
- A zener diode which can be used as a voltage regulator
- A diode which can be used as a rectifier
To solve this, we need to analyze the given I-V characteristics graph:
- The graph shows that the current remains constant after a certain reverse voltage is reached. This is a distinctive feature of a Zener diode.
- A Zener diode operates in the reverse breakdown region, where it maintains a constant voltage across it despite changes in current. This property is used for voltage regulation.
Now, let's reason through the options:
- Solar cell: The I-V characteristic of a solar cell typically shows a current generation with illumination, which is not present here.
- Transistor as an amplifier: Transistors have different characteristic curves for different configurations, and this I-V curve does not match any transistor mode.
- Zener diode as a voltage regulator: The depicted graph matches the behavior of a Zener diode in the reverse breakdown region, making this option correct.
- Diode as a rectifier: Rectifiers typically show forward-biased characteristics, which are not displayed here.
Therefore, the correct option is a Zener diode which can be used as a voltage regulator.
This choice is confirmed by the graph showing the constant current in reverse bias, indicative of a Zener diode's voltage regulating behavior.
Approach Solution -2
The I-V characteristics of the given device show a typical breakdown region where the voltage remains fairly constant while the current increases. This characteristic is a signature of a Zener diode in its breakdown region, which is used as a voltage regulator.
Thus, the correct answer is Option (3).
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