Question

The hybridization of aluminum in the complexes X and Y respectively is: 

• A. \( sp^2, sp^3 \)
• B. \( sp^3, sp^3d \)
• C. \( sp^3, sp^3 \)
• D. \( sp^3, sp^3d^2 \)

Hint:

The number of ligands and the geometry of the complex greatly influence the hybridization state of the central atom.

Answer 1

The Correct Option is D

Step 1: Identifying the hybridization states of X and Y.
In the given reaction, Y represents the \({AlCl}_3\) complex in aqueous solution.
\({AlCl}_3\) in aqueous solution forms \({[Al(H}_2{O})_6]^{3+}\), where aluminium has an \( sp^3d^2 \) hybridization due to its octahedral geometry.
X represents the hydrated form of Al, where Al is surrounded by six water molecules, maintaining an octahedral coordination with \( sp^3d^2 \) hybridization.
Step 2: Conclusion
Y (\({AlCl}_3\)) in aqueous solution undergoes hydration to form \({[Al(H}_2{O})_6]^{3+}\), which exhibits \( sp^3d^2 \) hybridization.
The correct answer is (4) \( sp^3, sp^3d^2 \).