Question:

The homonuclear complex in the following is:

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In a homonuclear complex, all atoms directly bonded to the central metal must be of the same element, like all nitrogen in \([\text{Co}(\text{NH}_3)_6]^{3+}\).
Updated On: May 20, 2025
  • \([\text{Co}(\text{NH}_3)_4\text{Br}_2]^+\)
  • \([\text{Co}(\text{C}_2\text{O}_4)(\text{NH}_3)_4]^+\)
  • \([\text{Co}(\text{NH}_3)_6]^{3+}\)
  • \([\text{Co}(\text{CN})_4\text{Cl}_2]^0\)
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The Correct Option is C

Solution and Explanation

A homonuclear complex has all coordinating atoms of the same element. Let's check: - (1) \([\text{Co}(\text{NH}_3)_4\text{Br}_2]^+\): Coordinating atoms are N (from \(\text{NH}_3\)) and Br. Not homonuclear.
- (2) \([\text{Co}(\text{C}_2\text{O}_4)(\text{NH}_3)_4]^+\): Coordinating atoms are O (from oxalate) and N. Not homonuclear.
- (3) \([\text{Co}(\text{NH}_3)_6]^{3+}\): All coordinating atoms are N (from \(\text{NH}_3\)). Homonuclear.
- (4) \([\text{Co}(\text{CN})_4\text{Cl}_2]^0\): Coordinating atoms are C (from \(\text{CN}^-\)) and Cl. Not homonuclear.
Thus, the homonuclear complex is \([\text{Co}(\text{NH}_3)_6]^{3+}\).
Thus, the correct answer is option 3.
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