Height (h) of cone = 15 cm
Let the radius of the cone be r.
Volume of cone = 1570 cm3
\(\frac{1}{3}\pi\)r²h = 1570 cm³
r² =\(\frac{\text{ (1570 cm³ × 3) }}{ \pi h}\)
r² = \(\frac{\text{(1570 cm³ × 3) }}{\text{ (3.14 × 15 cm) }}\)= 100 cm²
r = \(\sqrt{100}\) cm²
r = 10 cm
Therefore, the radius of the base of cone is 10 cm.
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.0g of oxygen? Which law of chemical combination will govern your answer?