Height (h) of cone = 15 cm
Let the radius of the cone be r.
Volume of cone = 1570 cm3
\(\frac{1}{3}\pi\)r²h = 1570 cm³
r² =\(\frac{\text{ (1570 cm³ × 3) }}{ \pi h}\)
r² = \(\frac{\text{(1570 cm³ × 3) }}{\text{ (3.14 × 15 cm) }}\)= 100 cm²
r = \(\sqrt{100}\) cm²
r = 10 cm
Therefore, the radius of the base of cone is 10 cm.
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.