Question:
The general solution of \( z = px + qy + p^2q^2 \) is
The general solution of \( z = px + qy + p^2q^2 \) is
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For first-order PDEs, substitute \( p = a \), \( q = b \) to form the general integral with constants.
Updated On: May 4, 2025
- \( z = ax + by \)
- \( z = px + qy + a^2b^2 \)
- \( z = ax + by + ab \)
- \( z = ax + by + a^2b^2 \)
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The Correct Option is D
Solution and Explanation
The function given is \( z = px + qy + p^2q^2 \), and we assume \( p = a \), \( q = b \) as constants (parameters of integration).
So the general solution is:
\[
z = ax + by + a^2b^2
\]
This matches option (4).
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