Question

The gas liberated on reaction of dilute sulphuric acid on zinc powder is:

• A. H\(_2\)
• B. O\(_2\)
• C. Cl\(_2\)
• D. CO\(_2\)

Hint:

Zinc reacts with dilute sulfuric acid to produce hydrogen gas and zinc sulfate.

Answer 1

The Correct Option is A

When zinc reacts with dilute sulphuric acid, hydrogen gas (\(H_2\)) is liberated. The reaction is as follows:
\[ \text{Zn (s)} + \text{H}_2\text{SO}_4 \text{(aq)} \rightarrow \text{ZnSO}_4 \text{(aq)} + \text{H}_2 \text{(g)} \]
Step 1: Reaction Analysis.
Zinc metal reacts with dilute sulfuric acid to produce zinc sulfate and hydrogen gas. This is a single displacement reaction. The zinc displaces the hydrogen from the acid and forms zinc sulfate, releasing hydrogen gas in the process.

Step 2: Analysis of Options.
- (A) \(H_2\) is the correct answer as it is released during the reaction of zinc with dilute sulfuric acid.
- (B) \(O_2\) is oxygen, which is not involved in this reaction.
- (C) \(Cl_2\) is chlorine, and this reaction does not produce chlorine gas.
- (D) \(CO_2\) is carbon dioxide, which is not produced in this reaction.

Step 3: Conclusion.
The gas released during the reaction of zinc with dilute sulfuric acid is hydrogen gas (\(H_2\)). Therefore, the correct answer is (A).