Step 1. Understanding the Function \( f(n) \): The function \( f(n) \) maps each natural number \( n \) (excluding 1) to its highest prime factor. For example:
\(f(10) = 5, \quad f(15) = 5, \quad f(18) = 3\)
Step 2. Checking if \( f(n) \) is One-One: For a function to be one-one (injective), each distinct input must map to a distinct output. However, different values of \( n \) can have the same highest prime factor. For instance:
\(f(10) = f(15) = 5\)
- Since different numbers can yield the same highest prime factor, \( f(n) \) is not one-one.
Step 3. Checking if \( f(n) \) is Onto: For \( f(n) \) to be onto (surjective), every natural number should appear as an output of \( f(n) \). However, not all natural numbers are prime. Since \( f(n) \) only outputs prime numbers, it cannot cover all natural numbers. Therefore, \( f(n) \) is not onto.
Since \( f(n) \) is neither one-one nor onto, the correct answer is \( (4) \).
Let A be the set of 30 students of class XII in a school. Let f : A -> N, N is a set of natural numbers such that function f(x) = Roll Number of student x.
Give reasons to support your answer to (i).
Find the domain of the function \( f(x) = \cos^{-1}(x^2 - 4) \).
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to: