Question

The force experienced by a proton moving in an electric field of intensity 3E is (e is the charge of the electron)

• A. Ee
• B. 2Ee
• C. 3Ee
• D. \(\frac{Ee}{2}\)
• E. \(\frac{Ee}{3}\)

Answer 1

The Correct Option is C

The force \( F \) experienced by a charged particle in an electric field is given by the formula: \[ F = qE \] Where: - \( q \) is the charge of the particle, - \( E \) is the electric field intensity. For a proton, the charge \( q \) is equal to \( +e \) (the charge of the electron). The intensity of the electric field is given as \( 3E \). Therefore, the force on the proton is: \[ F = e \times 3E = 3Ee \] Thus, the force experienced by the proton is \( 3Ee \).

The correct option is (C) : \(3Ee\)

Answer 2

The force \( F \) experienced by a charge \( q \) in an electric field \( E \) is given by: 
 
$$ F = qE $$ 
For a proton (which has charge \( +e \)) in an electric field of intensity \( 3E \): 

$$ F = e \cdot 3E = 3Ee $$ 

Answer: \( \boxed{3Ee} \)