Question

The following graph is obtained for the adsorption of a gas on the surface of a catalyst. The values of k and n are respectively \left( x\text{-axis} = \log p ; \, y\text{-axis} = \log \left( \frac{x}{m} \right) \includegraphics[width=0.3\linewidth]{78image.png}

• A. \(2, \frac{1}{m}\)
• B. \(1, 2\)
• C. \(100, 1\)
• D. \(m, 100\) \

Hint:

For adsorption isotherms, the slope and intercept of the graph provide key information regarding the rate of adsorption and the constants involved.

Answer 1

The Correct Option is C

The given graph is of the form \( x = \log p \) and \( y = \log \left( \frac{x}{m} \right) \). The slope of the graph is represented by \( m \), and it is related to the adsorption isotherm. The equation that follows from the graph is of the form: \[ k = \text{slope} \times \left( \frac{x}{m} \right) \] Here, from the graph, the slope is \( 100 \), so the value of \( n \) is 1. Therefore, the values of \( k \) and \( n \) are \( 100 \) and \( 1 \) respectively.