Question

The figure shows the path of a light ray through a triangular prism. In this phenomenon, the angle $\theta$ is given by:

Hint:

In cases involving refraction and critical angles, remember to use Snell's Law, $n_1 \sin \theta_1 = n_2 \sin \theta_2$, to calculate refractive indices or angles accurately.

Answer 1

For the given triangular prism, the angle $\theta$ is related to the refractive index of the material of the prism. Using Snell's law and geometrical principles, the relationship is given by: $$\boxed{\text{(A) } \sin^{-1} \sqrt{n^2 - 1}}.$$ \vspace{0.5cm}