Question

The figure shows the path of a light ray through a triangular prism. In this phenomenon, the angle \( \theta \) is given by:

Hint:

In cases involving refraction and critical angles, remember to use Snell's Law, \( n_1 \sin \theta_1 = n_2 \sin \theta_2 \), to calculate refractive indices or angles accurately.

Answer 1

For the given triangular prism, the angle \( \theta \) is related to the refractive index of the material of the prism. Using Snell's law and geometrical principles, the relationship is given by: \[ \boxed{\text{(A) } \sin^{-1} \sqrt{n^2 - 1}}. \] \vspace{0.5cm}