The work done during expansion or compression is given by:
\[
W = P \Delta V
\]
Where:
- \( P = 2 \times 10^5 \, \text{Nm}^2 \) (pressure),
- \( \Delta V = V_2 - V_1 = (15 - 10) \, \text{litres} = 5 \times 10^{-3} \, \text{m}^3 \).
Substitute the values:
\[
W = 2 \times 10^5 \times 5 \times 10^{-3} = 1000 \, \text{J}
\]
Thus, the work done is 1000 J.