Step 1: The escape velocity \( v_e \) is the minimum velocity required for a body to escape the gravitational field of a planet. It is given by the formula: \[ v_e = \sqrt{\frac{2GM}{R}}, \] where:
- \( G \) is the gravitational constant,
- \( M \) is the mass of the planet,
- \( R \) is the radius of the planet.
Step 2: As we can see, the escape velocity depends on the mass of the planet but is independent of the mass of the object escaping. The mass \( m \) of the object does not affect the escape velocity.
Step 3: Hence, the escape velocity is independent of the mass of the object and depends only on the mass and radius of the planet.

The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
A Wheatstone bridge is initially at room temperature and all arms of the bridge have same value of resistances \[ (R_1=R_2=R_3=R_4). \] When \(R_3\) resistance is heated, its resistance value increases by \(10%\). The potential difference \((V_a-V_b)\) after \(R_3\) is heated is _______ V. 