Question:

The equations of the circle which pass through the origin and makes intercepts of lengths $4$ and $8$ on the $x$ and $y$-axes respectively are

Updated On: Jun 17, 2022
  • $x^{2}+y^{2}\pm4x\pm8y=0$
  • $x^{2}+y^{2}\pm2x\pm4y=0$
  • $x^{2}+y^{2}\pm8x\pm16y=0$
  • $x^{2}+y^{2}\pm x\pm y=0$
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The Correct Option is A

Solution and Explanation

In $\Delta O A C, \,\,\,\,O C^{2}=2^{2}+4^{2}=20$

$\therefore$ Required equation of circle is
$(x \pm 2)^{2}+(y \pm 4)^{2} =20$
$\Rightarrow x^{2}+y^{2} \pm 4 x \pm 8 y =0$
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