The equation of the line perpendicular to 2x – 3y + 5 = 0 and making an intercept 3 with positive Y-axis is
The equation of the line perpendicular to 2x – 3y + 5 = 0 and making an intercept 3 with positive Y-axis is
- 3x + 2y – 6 = 0
- 3x + 2y – 12 = 0
- 3x + 2y – 7 = 0
- 3x + 2y + 6 = 0
The Correct Option is A
Solution and Explanation
Given equation of line is 2x-3y+5=0;
The slope of the given line is 2/3.
Therefore, the slope of the perpendicular to the given line is m= -\(\frac {3}{2}\).
Also, line intercept y-axis = 3, i.e., c = 3.
We know That
y = mx+c
y = -\(\frac {3}{2}\)x + 3
2y = -3x + 6
3x+2y-6=0
Therefore, the correct option is (A) 3x+2y-6=0
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