We are given the equations of the two equal sides of the isosceles triangle:
1. \( 7x - y + 3 = 0 \)
2. \( x + y - 3 = 0 \)
First, we solve these two equations to find the coordinates of the vertex of the isosceles triangle.
From equation 2, we solve for \( y \):
\[
y = 3 - x
\]
Substitute this into equation 1:
\[
7x - (3 - x) + 3 = 0
\]
Simplifying:
\[
7x - 3 + x + 3 = 0 \\
8x = 0 \\
x = 0
\]
Now, substitute \( x = 0 \) into \( y = 3 - x \):
\[
y = 3
\]
Thus, the vertex of the triangle is at \( (0, 3) \).
Now, we find the slope of the third side. The third side passes through the point \( (0, 3) \) and is connected to the point on the x-axis, which is \( (3, 0) \) (from the second equation). The slope \( m \) is given by:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substitute the points \( (x_1, y_1) = (0, 3) \) and \( (x_2, y_2) = (3, 0) \):
\[
m = \frac{0 - 3}{3 - 0} = \frac{-3}{3} = -1
\]
Thus, the slope of the third side is \( m = -3 \).