Question:
The energy of a photon is equal to the kinetic energy of a
proton. The energy of the photon is E. Let $ \lambda_1 $ be the
de-Broglie wavelength of the proton and $ \lambda_2 $ be the
wavelength of the photon. The ratio $ \frac{\lambda_1}{\lambda_2} $
is proportional to
The energy of a photon is equal to the kinetic energy of a
proton. The energy of the photon is E. Let $ \lambda_1 $ be the
de-Broglie wavelength of the proton and $ \lambda_2 $ be the
wavelength of the photon. The ratio $ \frac{\lambda_1}{\lambda_2} $
is proportional to
Updated On: Jul 29, 2022
- $ E^0 $
- $ E^{\frac{1}{2}} $
- $ E^{-1} $
- $ E^{-2} $
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The Correct Option is B
Solution and Explanation
$ \frac{\lambda_1}{\lambda_2} = \frac{\frac{h}{\sqrt2mE}}{\frac{hc}{E}} \, \, or\, \, \frac{\lambda_1}{\lambda_2} ? E^{1/2} $
Therefore, the correct option is (b)
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Concepts Used:
Kinetic energy
Kinetic energy of an object is the measure of the work it does as a result of its motion. Kinetic energy is the type of energy that an object or particle has as a result of its movement. When an object is subjected to a net force, it accelerates and gains kinetic energy as a result. Kinetic energy is a property of a moving object or particle defined by both its mass and its velocity. Any combination of motions is possible, including translation (moving along a route from one spot to another), rotation around an axis, vibration, and any combination of motions.
