Let $f:(-1,1)\rightarrow$ R be such that $f(cos 4 \theta)=\frac{2}{2-sec^2 \theta}$ for $\theta \in \Bigg(0,\frac{\pi}{4}\Bigg)\cup\Bigg(\frac{\pi}{4},\frac{\pi}{2}\Bigg).$
Then, the value(s) of $f\Bigg(\frac{1}{3}\Bigg)$ is are
- $1-\sqrt{\frac{3}{2}}$
- $1+\sqrt{\frac{3}{2}}$
- $1-\sqrt{\frac{2}{3}}$
- $1+\sqrt{\frac{2}{3}}$
The Correct Option is B
Solution and Explanation
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Concepts Used:
Functions
A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.
Kinds of Functions
The different types of functions are -
One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.
Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.
Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.
Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.
Read More: Relations and Functions