Step 1: Using the photon energy formula.
The energy of a photon is related to its frequency by the formula:
\[
E = h \nu
\]
where:
- \( E = 6.63 \times 10^{-34} \, \text{J} \),
- \( h = 6.63 \times 10^{-34} \, \text{Js} \) (Planck's constant),
- \( \nu \) is the frequency of the photon.
Step 2: Solving for frequency.
Rearrange the formula to solve for \( \nu \):
\[
\nu = \frac{E}{h} = \frac{6.63 \times 10^{-34}}{6.63 \times 10^{-34}} = 1 \, \text{Hz}
\]
Step 3: Conclusion.
The frequency of the photon is \( 1 \, \text{Hz} \), so the correct answer is (A).