Question:

The end points of the major axis of an ellipse are (2, 4) and (2,-8). If the distance between foci of this ellipse is 4, then the equation of the ellipse is

Updated On: Dec 2, 2024
  • \(\frac{(x-2)^2}{32}+\frac{(y+2)^2}{36}=1\)
  • \(\frac{(x-4)^2}{32}+\frac{(y+2)^2}{36}=1\)
  • \(\frac{(x-2)^2}{36}+\frac{(y+2)^2}{32}=1\)
  • \(\frac{(x-2)^2}{32}+\frac{(y-4)^2}{36}=1\)
  • \(\frac{(x-2)^2}{36}+\frac{(y-4)^2}{32}=1\)
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The Correct Option is A

Solution and Explanation

The correct option is (A) : \(\frac{(x-2)^2}{32}+\frac{(y+2)^2}{36}=1\)
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