The question asks about the stability of copper in its different oxidation states, Cu(I) and Cu(II). To determine which is more stable under standard conditions, we need to consider both the electronic configuration and some known empirical facts about copper salts.
Electronic Configuration:
Cu(II) has one less electron in the d-orbital compared to Cu(I). In terms of electronic configuration, a completely filled or half-filled d-orbital is generally more stable. Yet, in this case, the d9 configuration of Cu(II) may initially appear less stable compared to the d10 of Cu(I).
Stability of Copper Oxidation States:
The stability of different oxidation states of an element can be influenced by various factors, including lattice energy, solvation energy, and the Jahn-Teller effect:
Considering the above factors, Cu(II) is generally more stable than Cu(I) in aqueous solution, and the empirical evidence from copper salts often shows that Cu(II) compounds are more common and stable.
Conclusion:
The correct answer is: Cu(II) is more stable. Therefore, the assertion that "Cu(II) is more stable" is supported by the greater stability of Cu(II) due to factors like the Jahn-Teller effect and higher hydration energy.
Among, Sc, Mn, Co and Cu, identify the element with highest enthalpy of atomisation. The spin only magnetic moment value of that element in its +2 oxidation state is _______BM (in nearest integer).
Given below are two statements :
Statement I : CrO\( _3 \) is a stronger oxidizing agent than MoO\( _3 \)
Statement II : Cr(VI) is more stable than Mo(VI) In the light of the above statements, choose the correct answer from the options given below
Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).
The magnitude of heat exchanged by a system for the given cyclic process ABC (as shown in the figure) is (in SI units):
