The question asks about the stability of copper in its different oxidation states, Cu(I) and Cu(II). To determine which is more stable under standard conditions, we need to consider both the electronic configuration and some known empirical facts about copper salts.
Electronic Configuration:
Cu(II) has one less electron in the d-orbital compared to Cu(I). In terms of electronic configuration, a completely filled or half-filled d-orbital is generally more stable. Yet, in this case, the d9 configuration of Cu(II) may initially appear less stable compared to the d10 of Cu(I).
Stability of Copper Oxidation States:
The stability of different oxidation states of an element can be influenced by various factors, including lattice energy, solvation energy, and the Jahn-Teller effect:
Considering the above factors, Cu(II) is generally more stable than Cu(I) in aqueous solution, and the empirical evidence from copper salts often shows that Cu(II) compounds are more common and stable.
Conclusion:
The correct answer is: Cu(II) is more stable. Therefore, the assertion that "Cu(II) is more stable" is supported by the greater stability of Cu(II) due to factors like the Jahn-Teller effect and higher hydration energy.
A laser beam has intensity of $4.0\times10^{14}\ \text{W/m}^2$. The amplitude of magnetic field associated with the beam is ______ T. (Take $\varepsilon_0=8.85\times10^{-12}\ \text{C}^2/\text{N m}^2$ and $c=3\times10^8\ \text{m/s}$)