Step 1: Analyze statement (i).
In \( \text{Mn}_2\text{O}_7 \), manganese has the highest oxidation state of +7, which is indeed the highest oxidation state of Mn in its compounds. So, statement (i) is correct.
Step 2: Analyze statement (ii).
\( \text{MnO} \) is \( \text{Mn}^{2+} \), and \( \text{Mn}_2\text{O}_7 \) contains \( \text{Mn}^{7+} \). Due to the highly ionic nature of \( \text{Mn}^{2+} \) in \( \text{MnO} \), and the covalent nature of \( \text{Mn}_2\text{O}_7 \) (due to the high oxidation state of Mn), it is correct to say that \( \text{MnO} \) is more ionic than \( \text{Mn}_2\text{O}_7 \). So, statement (ii) is correct.
Step 3: Analyze statement (iii).
\( \text{Mn}_2\text{O}_7 \) has a structure where the two Mn atoms are connected by an oxygen atom (bridging oxygen). So, statement (iii) is correct.
Step 4: Analyze statement (iv).
The oxidation state of Mn is indeed maximum in oxo compounds like \( \text{Mn}_2\text{O}_7 \), where Mn has an oxidation state of +7. So, statement (iv) is correct.
Step 5: Conclusion.
All the statements (i), (ii), (iii), and (iv) are correct. Therefore, the correct answer is (2) All (i), (ii), (iii) and (iv) are correct.