Question:
The electric flux for Gaussian surface A that enclose the charged particles in free space is
(given $q_1= - 14\, nc, q_2 = 78.85\, nC, q_3 = - 56\, nC$)
The electric flux for Gaussian surface A that enclose the charged particles in free space is
(given $q_1= - 14\, nc, q_2 = 78.85\, nC, q_3 = - 56\, nC$)
Updated On: Jul 28, 2023
- $10^3\,Nm^2C^{-1} $
- $10^3\,CN^{-1}m^{-2} $
- $6.32 \times 10^3\,Nm^2C^{-1}$
- $6.32 \times 10^3\,CN^{-1}m^{-2} $
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The Correct Option is A
Solution and Explanation
Electric flux $=\frac{q}{\varepsilon_{0}}$
$=\frac{(-14+7885-56) \times 10^{-9}}{885 \times 10^{-12}}=\frac{885 \times 10^{-9}}{885 \times 10^{-12}}$
$=1000\, Nm ^{2} \,C ^{-1}$
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Concepts Used:
Electric Dipole
An electric dipole is a pair of equal and opposite point charges -q and q, separated by a distance of 2a. The direction from q to -q is said to be the direction in space.
p=q×2a
where,
p denotes the electric dipole moment, pointing from the negative charge to the positive charge.
Force Applied on Electric Dipole
