\( 25 \, \text{J} \)
\( 50 \, \text{J} \)
To find the kinetic energy of an object, we use the formula for kinetic energy, which is given by:
\[ KE = \frac{1}{2}mv^2 \]
where:
Given that the mass \( m = 0.5 \, \text{kg} \) and the velocity \( v = 10 \, \text{m/s} \), we can substitute these values into the formula:
\[ KE = \frac{1}{2} \times 0.5 \, \text{kg} \times (10 \, \text{m/s})^2 \]
First, calculate the square of the velocity:
\[ (10 \, \text{m/s})^2 = 100 \, \text{m}^2/\text{s}^2 \]
Then, multiply by the mass and divide by 2:
\[ KE = \frac{1}{2} \times 0.5 \times 100 \]
\[ KE = 0.25 \times 100 = 25 \, \text{J} \]
Thus, the kinetic energy of the object is \( \boxed{25 \, \text{J}} \), indicating that there was an error in the provided solution options.
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):