The electric field and the potential of an electric dipole vary with distance 'r' as
1/r2 and 1/r3
1/r and 1/r2
1/r3 and 1/r2
1/r2 and 1/r
Electric Field:
\( E_g = \frac{1}{4 \pi \epsilon_0} \frac{p}{r^3} \sqrt{3 \cos^2 \theta + 1} \)
Electric Potential:
\( V_g = \frac{1}{4 \pi \epsilon_0} \frac{p \cos \theta}{r^2} \)
Therefore, the correct option is: D.
Given:
\( E = K r^{3/2} \quad \text{and} \quad E \propto r^{3/1} \)
Similarly, for the potential \( V \), we have:
\( V = K r^2 p \cos \theta \quad \text{and} \quad V \propto r^2 \)
Thus, the relationships show that:
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where