Question:
The eccentricity of the ellipse \(\frac{x^2}{36}+\frac{y^2}{16}=1\) is
The eccentricity of the ellipse \(\frac{x^2}{36}+\frac{y^2}{16}=1\) is
Updated On: Jun 10, 2024
- \(\frac{\sqrt{5}}{3}\)
- \(\frac{\sqrt{5}}{6}\)
- \(\frac{\sqrt{30}}{6}\)
- \(\frac{\sqrt{10}}{6}\)
- \(\frac{\sqrt{30}}{7}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{\sqrt{5}}{3}\)
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