The distance of the Sun from Earth is \(1.5 × 10^{11}\) \(m\), and its angular diameter is \((2000)\) \(s\) when observed from the earth. The diameter of the Sun will be :
- \(2.45 × 10^{10 }\) \(m\)
\(1.45 × 10^{10}\; m\)
- \(1.45 × 10^9 \;m\)
- \(0.14 × 10^9 \;m\)
The Correct Option is C
Solution and Explanation
The diameter of the Sun will be :
Diameter = \(r × δ\)
=\(1.5×10^{ 11}×(2000)×\bigg(\frac{1}{3600}\bigg)×\bigg(\frac{x}{180}\bigg)\)
= \(1.45 × 10^9\) \(m\)
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Concepts Used:
Distance and Displacement
Distance
Distance is the sum of the length of the path traveled by an object from one place to another. The path may or may not be directly from the initial point to the final point. It is a scalar quantity that only has a magnitude, and does not have any direction.
Speed = Distance / Time
Distance= Speed x Time
D = S x T
Displacement
Displacement is the length of the shortest path from the initial point to the final point. It is a vector quantity that has magnitude as well as direction.
Velocity= Displacement / Time Therefore,
Displacement = Velocity x Time.
D = V x T
The Difference Between Distance and Displacement are:
