Question:
The distance between the foci of a hyperbola is 16 and its eccentricity is \(\sqrt2\). Its equation is
The distance between the foci of a hyperbola is 16 and its eccentricity is \(\sqrt2\). Its equation is
Updated On: Apr 17, 2024
- 2x2 - 3y2 = 7
- x2 - y2 = 32
- y2 - x2 = 32
- \(\frac{x^2}{4}-\frac{y^2}{9}=1\)
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The Correct Option is B
Solution and Explanation
The correct answer is (B) :x2 - y2 = 32 .
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