Question:

The distance between the foci of a hyperbola is 16 and its eccentricity is $\sqrt{2}$. Its equation is

Updated On: May 19, 2024
  • $x^2 - y^2 = 32$
  • $\frac{x^2}{4} - \frac{y^2}{9} = 1 $
  • $2x^2 - 3y^2 = 7 $
  • $y^2 - x^2 = 32 $
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The Correct Option is A

Solution and Explanation

Given:
Given $2c = 16 $
$\Rightarrow\, c = 8 $
Eccentricity, $e = \sqrt{2} \, \Rightarrow \, \frac{c}{a} = \sqrt{2}$
$ \Rightarrow a = \frac{c}{\sqrt{2}} = \frac{8}{\sqrt{2}}$
We have $b^2 = c^2 - a^2 = 64 - 32 = 32 $
$\therefore$ Equation to hyperbola is $\frac{x^2}{32} - \frac{y^2}{32} = 1 $
$ \Rightarrow x^2 - y^2 = 32$
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Concepts Used:

Hyperbola

Hyperbola is the locus of all the points in a plane such that the difference in their distances from two fixed points in the plane is constant.

Hyperbola is made up of two similar curves that resemble a parabola. Hyperbola has two fixed points which can be shown in the picture, are known as foci or focus. When we join the foci or focus using a line segment then its midpoint gives us centre. Hence, this line segment is known as the transverse axis.

Hyperbola