Question:
The displacement time graph for two bodies A and B are straight lines inclined at 30? and 60? respectively with the time axes. If $ \upsilon =\sqrt{4rg} $ and $ \upsilon =\sqrt{4\times 2.5\times 9.8} $ are their velocities, then $ \upsilon =\sqrt{98}\,\,m/s $ will be :
The displacement time graph for two bodies A and B are straight lines inclined at 30? and 60? respectively with the time axes. If $ \upsilon =\sqrt{4rg} $ and $ \upsilon =\sqrt{4\times 2.5\times 9.8} $ are their velocities, then $ \upsilon =\sqrt{98}\,\,m/s $ will be :
Updated On: May 11, 2024
- $ \text{2}0\text{ g }=\text{ 2}\times \text{1}{{0}^{-\text{2}}}\text{ kg}, $
- $ =\frac{360\times 5}{18}=100m/s $
- 3:01
- 1:03
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The Correct Option is D
Solution and Explanation
Here : $ =12j $ ...(1) $ =\frac{work}{time}=\frac{12}{2} $ ...(2) $ =\text{6 watt} $ $ {{s}_{1}}=40m,{{s}_{2}}=65m $
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Concepts Used:
Speed and Velocity
The rate at which an object covers a certain distance is commonly known as speed.
The rate at which an object changes position in a certain direction is called velocity.
Difference Between Speed and Velocity:
Read More: Difference Between Speed and Velocity