The displacement time graph for two bodies A and B are straight lines inclined at 30? and 60? respectively with the time axes. If $ \upsilon =\sqrt{4rg} $ and $ \upsilon =\sqrt{4 imes 2.5 imes 9.8} $ are their velocities, then $ \upsilon =\sqrt{98}\,\,m/s $ will be :

Question

The displacement time graph for two bodies A and B are straight lines inclined at 30? and 60? respectively with the time axes. If $ \upsilon =\sqrt{4rg} $ and $ \upsilon =\sqrt{4	imes 2.5	imes 9.8} $ are their velocities, then $ \upsilon =\sqrt{98}\,\,m/s $ will be :

cdquestions Admin · Accepted Answer

Here : $ =12j $ ...(1) $ =\frac{work}{time}=\frac{12}{2} $ ...(2) $ =	ext{6 watt} $ $ {{s}_{1}}=40m,{{s}_{2}}=65m $

Answer

$ ext{2}0 ext{ g }= ext{ 2} imes ext{1}{{0}^{- ext{2}}} ext{ kg}, $

Answer

$ =\frac{360 imes 5}{18}=100m/s $

Answer

Answer

The displacement time graph for two bodies A and B are straight lines inclined at 30? and 60? respectively with the time axes. If $\upsilon =\sqrt{4rg}$ and $\upsilon =\sqrt{4\times 2.5\times 9.8}$ are their velocities, then $\upsilon =\sqrt{98}\,\,m/s$ will be :

The Correct Option is D

Solution and Explanation

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