The displacement of a particle executing simple harmonic motion is given by x = 2cos(t) where t is the time in seconds then the time period of the particle is:
π second
2π second
3π second
0.5π second
The correct option is: (B) 2π second.
The equation for simple harmonic motion (SHM) is given by:
x = A cos(ωt)
Where:
In the provided equation, x = 2cos(t), we can see that the amplitude is 2.
For simple harmonic motion, the relation between the angular frequency (ω) and the time period (T) is:
ω = 2π / T
Given that ω = 1 (since the coefficient of 't' in the equation is 1), we can rearrange the relation to solve for the time period:
T = 2π / ω
Substituting the value of ω = 1:
T = 2π / 1 = 2π seconds.
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Read More: Simple Harmonic Motion
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