The power \( P \) of a lens is defined as the reciprocal of its focal length. The dimensional formula for the power of a lens is the same as that of the inverse of length, which is \( [L^{-1}] \). Since power involves only the length dimension, the mass \( M \) and time \( T \) have exponents of 0.
Hence, the dimensional formula for the power of a lens is \( [L^{-1} M^0 T^{0}] \).
The correct option is (A) : \([L^{-1} M^0 T^{0}]\)
The power of a lens is defined as the reciprocal of the focal length (in meters). That is:
$P = \frac{1}{f}$
The dimensional formula for focal length is $[L]$. Hence, the dimensional formula for power is:
$[L^{-1}]$
Since it has no dependence on mass or time, the complete dimensional formula becomes:
Correct answer: [L-1M0T0]
A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?