Question:

The diameter of a metallic ball is 4.2 cm. What is the mass of the ball, if the density of the metal is 8.9 g per cm3 ?

Updated On: Nov 17, 2023
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Solution and Explanation

Radius of the metallic ball, r = \(\frac{4.2}{2}\) cm = 2.1cm 
The volume of the metallic ball = \(\frac{4}{3}\pi r^3 \)
\(\frac{4}{3}\) × \(\frac{22}{7}\) × 2.1cm × 2.1cm × 2.1cm 
= 38.808 cm³

Mass = Volume × Density
Mass of the metallic ball = 38.808 cm3 × 8.9g / cm³
= 345.3912 g
= 345.39 g
Hence, the mass of the ball is 345.39 g (approximately).

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