Radius of the metallic ball, r = \(\frac{4.2}{2}\) cm = 2.1cm
The volume of the metallic ball = \(\frac{4}{3}\pi r^3 \)
= \(\frac{4}{3}\) × \(\frac{22}{7}\) × 2.1cm × 2.1cm × 2.1cm
= 38.808 cm³
Mass = Volume × Density
Mass of the metallic ball = 38.808 cm3 × 8.9g / cm³
= 345.3912 g
= 345.39 g
Hence, the mass of the ball is 345.39 g (approximately).
List-I | List-II | ||
(A) | Volume of cone | (I) | \(\frac{1}{3}\pi h(r_1^2+r_2^2+r_1r_2)\) |
(B) | Volume of sphere | (II) | \(\frac{1}{3}\pi r^2h\) |
(C) | Volume of Frustum | (III) | \(\pi r^2h\) |
(D) | Volume of cylinder | (IV) | \(\frac{4}{3}\pi r^3\) |
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.