Radius of the metallic ball, r = \(\frac{4.2}{2}\) cm = 2.1cm
The volume of the metallic ball = \(\frac{4}{3}\pi r^3 \)
= \(\frac{4}{3}\) × \(\frac{22}{7}\) × 2.1cm × 2.1cm × 2.1cm
= 38.808 cm³
Mass = Volume × Density
Mass of the metallic ball = 38.808 cm3 × 8.9g / cm³
= 345.3912 g
= 345.39 g
Hence, the mass of the ball is 345.39 g (approximately).
(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
