The determinant of a \( 3 \times 3 \) matrix A is 30. If 2 and 3 are two Eigenvalues of A, then the third Eigenvalue of A (in integer) is ________________.
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For a square matrix, the determinant is the product of its Eigenvalues.
The determinant of a matrix is the product of its Eigenvalues. Given that two Eigenvalues of \( A \) are 2 and 3, we can use the following relation for the determinant of the matrix:
\[
\text{det}(A) = \lambda_1 \times \lambda_2 \times \lambda_3.
\]
Substituting the given values:
\[
30 = 2 \times 3 \times \lambda_3.
\]
Solving for \( \lambda_3 \):
\[
\lambda_3 = \frac{30}{6} = 5.
\]
Final Answer:
\[
\boxed{5}.
\]