The decomposition of NH3 on platinum surface is zero order reaction. What are the rates of production of N2 and H2 if k = 2.5 x 10-4 mol-1Ls-1?
The decomposition of NH3 on platinum surface is zero order reaction. What are the rates of production of N2 and H2 if k = 2.5 x 10-4 mol-1Ls-1?
Solution and Explanation
The decomposition of NH3 on platinum surface is represented by the following equation.
\(2NH_3(g) → N_2(g) + 3H_2(G)\)
Therefore,
\(Rate = -\frac 12 \frac {d[NH_3]}{dt} = \frac {d[N_2]}{dt} = \frac 13 \frac {d[H_2]}{dt}\)
However,it is given that the reaction is of zero order
Therefore
\(-\frac 12 \frac {d[NH_3]}{dt} = \frac {d[N_2]}{dt} = \frac 13 \frac {d[H_2]}{dt}\) = \(k = 2.5 \times 10^{-4} mol L^{-1} s^{-1}\)
Therefore, the rate of production of N2 is
\(\frac { d[N_2]}{dt} = 2.5 \times 10^{-4} mol L^{-1} s^{-1}\)
And, the rate of production of H2 is
\(\frac {d[H_2]}{dt} = 3\times 2.5\times 10^{-4} mol L^{-1} s^{-1}\)
= \(7.5\times 10^{-4} mol L^{-1} s^{-1}\)
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Concepts Used:
Order of Reaction
The Order of reaction refers to the relationship between the rate of a chemical reaction and the concentration of the species taking part in it. In order to obtain the reaction order, the rate equation of the reaction will given in the question.
Characteristics of the reaction order
- Reaction order represents the number of species whose concentration directly affects the rate of reaction.
- It can be obtained by adding all the exponents of the concentration terms in the rate expression.
- The order of reaction does not depend on the stoichiometric coefficients corresponding to each species in the balanced reaction.
- The reaction order of a chemical reaction is always defined with the help of reactant concentrations and not with product concentrations.
- Integer or a fraction form the value of the order of reaction will be there and it can be zero.