Question:

The cyanide ion $CN^-$ and $N_2$ are isoelectronic, but in contrast to $CN^-$ , $N_2$ is chemically inert because of

Updated On: May 12, 2022
  • low bond energy
  • absence of bond polarity
  • unsymmetrical electron distribution
  • presence of more number of electron in bonding orbitals
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The Correct Option is B

Solution and Explanation

$N_2$ is a neutral, non-polar, inert molecule while $CN^-$ is a
highly polar, highly active ion.
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Concepts Used:

Group 14 Elements

The group 14 elements are also known as the carbon group. Sometimes it is also called crystallogens. The group 14 elements can be found on the right side of the periodic table. The elements of the carbon group are: 

  • Carbon - C
  • Silicon - Si
  • Germanium - Ge
  • Tin - Sn
  • Lead - Pb
  • Flerovium - FI

The group 14 elements or the carbon family belongs to the p-block of the periodic table. The carbon group is also the second group in the p-block.

Electronic Configuration:

The arrangement of electrons in the orbitals of a molecule or atom is known as electronic configuration. The general electronic configuration of the group 14 elements is ns2np2.

All group 14 elements have 4 electrons in the outer shell. Hence, the valency of the carbon family or group 14 elements is 4.

Properties of Group 14 Elements:

  • Covalent Radii
  • Ionization Enthalpy
  • Electronegativity
  • Metallic Character
  • Density
  • Four Covalent Compounds
  • The Melting and Boiling Points