Question:

The curve described parametrically by $x = t^2 + 2t - 1, y = 3t + 5$ represents

Updated On: Sep 3, 2024
  • an ellipse
  • a hyperbola
  • a parabola
  • a circle
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The Correct Option is C

Solution and Explanation

Given $x = t^2 + 2t-1 \; \& \; y = 3t + 5$
$\Rightarrow \; x = t^2 + 2t + 1-2 \; \& \; y = 3t + 3+2$
$\Rightarrow \; x = (t+1)^2 -2 \; \& \; y = 3(t + 1) + 2 (2)$
$\Rightarrow (t+1) = \sqrt{ x + 2}$ .......... (1)
$\therefore$ Equation (2) becomes [using equation (1)]
$y = 3 \sqrt{ x + 2} + 2$
$\Rightarrow \; y - 2 = 3 \sqrt{x +2}$
squaring both sides, we get
$(y-2)^2 = 9 (x + 2)$
$\Rightarrow \; Y^2 =9X$ where $Y = y - 2 \; \& \; X = x + 2$
This equation represents a parabola
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Concepts Used:

Parabola

Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).

Parabola


 

 

 

 

 

 

 

 

 

Standard Equation of a Parabola

For horizontal parabola

  • Let us consider
  • Origin (0,0) as the parabola's vertex A,
  1. Two equidistant points S(a,0) as focus, and Z(- a,0) as a directrix point,
  2. P(x,y) as the moving point.
  • Let us now draw SZ perpendicular from S to the directrix. Then, SZ will be the axis of the parabola.
  • The centre point of SZ i.e. A will now lie on the locus of P, i.e. AS = AZ.
  • The x-axis will be along the line AS, and the y-axis will be along the perpendicular to AS at A, as in the figure.
  • By definition PM = PS

=> MP2 = PS2 

  • So, (a + x)2 = (x - a)2 + y2.
  • Hence, we can get the equation of horizontal parabola as y2 = 4ax.

For vertical parabola

  • Let us consider
  • Origin (0,0) as the parabola's vertex A
  1. Two equidistant points, S(0,b) as focus and Z(0, -b) as a directrix point
  2. P(x,y) as any moving point
  • Let us now draw a perpendicular SZ from S to the directrix.
  • Then SZ will be the axis of the parabola. Now, the midpoint of SZ i.e. A, will lie on P’s locus i.e. AS=AZ.
  • The y-axis will be along the line AS, and the x-axis will be perpendicular to AS at A, as shown in the figure.
  • By definition PM = PS

=> MP2 = PS2

So, (b + y)2 = (y - b)2 + x2

  • As a result, the vertical parabola equation is x2= 4by.