Question:

The critical angle for glass-water boundary is C. If $ {{\mu }_{g}}=1.5 $ 1.5 and $ {{\mu }_{\omega }}=\frac{4}{3} $ then the value of C is:

Updated On: May 12, 2022
  • $ {{\sin }^{-1}}\left( \frac{3}{2} \right) $
  • $ {{\sin }^{-1}}\left( \frac{4}{3} \right) $
  • $ {{\sin }^{-1}}\left( \frac{8}{9} \right) $
  • $ {{\sin }^{-1}}\left( \frac{1}{2} \right) $
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The Correct Option is C

Solution and Explanation

From the relation $ \sin C=\frac{{{\mu }_{w}}}{{{\mu }_{g}}}=\frac{4/3}{3/2}=\frac{8}{9} $ $ C={{\sin }^{-1}}\frac{8}{9} $
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